LATEST

    LDC EXAM PREPARATION    ||         SI / BDO EXAM PREPARATION 2020    ||        PREVIOUS QUESTIONS 2020 DEGREE LEVEL     ||        PREVIOUS QUESTIONS LDC     PSC EXAM PROGRAMME 2020     ||        TODAY'S EXAM RESULTS 2020    ||        FINAL ANSWER KEY    ||    FREE STUDY MATERIALS (LDC)     ||    FREE STUDY MATERIALS (DEGREE LEVEL)     ||    CURRENT AFFAIRS-MALAYALAM 2020     ||    CURRENT AFFAIRS-ENGLISH 2020

Monday, 29 April 2019

MATHS SOLVED IN STEPS: Age Related Problems - 03

21. A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, what was the son's age five
years back?
A. 20 years B. 18 years C. 14 years D. 22 years
Answer : Option C
Explanation :
Let the son's present age be x years.
Then, (38 - x) = x
=> 2x = 38
=> x = 38/2 = 19
Son's age 5 years back = 19-5 = 14


22. Ayisha's age is 1/6th of her father's age. Ayisha 's father's age will be twice the age of Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha 's present age.n's age 5 years back = 19-5 = 14
A. 10 years      B. 18 years   C. 8 years D. 5 years
Answer : Option D
Explanation :
Consider Ayisha's present age = x
Then her father's age = 6x
Given that Ayisha 's father's age will be twice the age of Shankar's age after 10 years
=> Shankar's age after 10 years = ½ (6x + 10) =
3x + 5
Also given that Shankar's eight birthdays was celebrated two years before =>
Shankar's age after 10 years = 8 + 12 = 20
=> 3x + 5 = 20
=> x = 15/3 = 5
=> Ayisha 's present age = 5 years

23.The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, what will be son's age?
A 23 years     B. 22 years      C. 21 years   D. 20 years
Answer : Option D
Explanation :
Let the present age of the son = x, then
Present age of the father = 60-x
Six years ago father's age was 5 times the age of the son
=> (60-x)-6 = 5(x-6)
=> 84 = 6x
=> x = 84/6 = 14
Son's age after 6 years = x + 6 = 14 + 6 = 20


24.Kiran is younger than Bineesh by 7 years and their ages are in the respective ratio of 7 : 9, how old is Kiran?
A. 25      B. 24.5     C. 24   D. 23.5
Answer : Option B
Explanation :
Let the ages of Kiran and Bineesh are 7x and 9x respectively
7x = 9x-7
=> x = 7/2 = 3.5
Kiran's age = 7x = 7 × 3.5 = 24.5

25.Six years ago, the ratio of the ages of Vimal and Saroj was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Saroj's age at present?
A. 18     B. 17     C. 16     D. 15
Answer : Option C
Explanation :
Given that , six years ago, the ratio of the ages of Vimal and Saroj = 6 : 5
Hence we can assume that
The age of Vimal six years ago = 6x
The age of Saroj six years ago = 5x
After 4 years, the ratio of their ages = 11 : 10
=> (6x+10) / (5x + 10) = 11/10
=> 10(6x + 10) = 11(5x + 10)
=> 5x = 10
=> x = 10/5 = 2
Saroj's present age = 5x + 6 = 5×2 +6 = 16

26.One year ago sunu's & Manu's age was 6:7 respectively. Four years hence, the ratio would become 7:8. How old is sunu ?
A. 31     B. 36    C. 37     D. 30
Answer : Option A
Explanation :
Let sunu's & manu's ages one year ago be 6x & 7x years respectively. Then sunu's age four years hence
= (6x+1)+4=6x+5 years
Manu's age four years hence= (7x+1)+4=7x+5 years
ie 6x+5/7x+5=7/8
=> 8(6x+5)=7(7x+5)
=> 48x+40=49x+35
=> 49x-48x=40-35
=> x=5
hence sunu's present age is=6x+1 = 6 x 5+1=30+1=31 years

27. My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born?
A. 35     B. 34     C. 33     D.32
Answer : Option D
Explanation :
Let my age = x
Then My brother's age = x + 3
My mother's age = x + 26
My sister's age = (x + 3) + 4 = x + 7
My Father's age = (x + 7) + 28 = x + 35
=> age my father when my brother was born = x + 35 – (x + 3) = 32
* MATHS (SOLVED IN STEPS ==> Ratio and Proportion
* MATHS (SOLVED IN STEPS ==> Progressions
* MATHS (SOLVED IN STEPS ==> Percentage
* MATHS (SOLVED IN STEPS ==> Surds and Indices
* MATHS (SOLVED IN STEPS ==> Calendar
* MATHS (SOLVED IN STEPS ==> Square and cube
* MATHS (SOLVED IN STEPS ==> Simplification
* MATHS (SOLVED IN STEPS ==> Problems on Average
* MATHS (SOLVED IN STEPS ==> HCF & LCM 
* MATHS (SOLVED IN STEPS ==> Profit and Loss
* MATHS (SOLVED IN STEPS ==> Problems on Trains 
* MATHS (SOLVED IN STEPS ==> Pipe and Cisterns
* MATHS (SOLVED IN STEPS ==> ODD MAN
* MATHS (SOLVED IN STEPS ==> TIME & WORK


Related Links
* KERALA PSC EXAM PROGRAMME - Click here
LDC/ LGS/ VEO Questions and Answers Click here
CURRENT AFFAIRS (ENGLISH) ---> Click here
GENERAL KNOWLEDGE QUESTIONS AND ANSWERS (English) ---> Click here
Information Technology (Questions & Answers )  ---> Click here
GENERAL SCIENCE - QUESTIONS AND ANSWERS (English) - Click here
FACTS ABOUT INDIA - Click here
FACTS ABOUT KERALA Click here
GEOGRAPHY AND ECONOMICS Click here
FAMOUS PERSONALITIES - QUESTIONS & ANSWERS Click here
* MATHS/ARITHMETIC/MENTAL ABILITY---> Click here
PSC PREVIOUS / SOLVED QUESTION PAPERS ---> Click here
NEW JOBS Click here
* SCERT KERALA TEXT BOOKS FOR CLASS II, IV, VI, VIII, IX, X, XII – FREE DOWNLOAD ---> Click here
* NCERT & CBSE TEXT BOOKS FOR ALL CLASSES – FREE DOWNLOAD ---> Click here
* NCERT & CBSE TEXT BOOKS SOLUTIONS FOR ALL CLASSES ---> Click here
Loading...

No comments:

Post a comment