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Monday, 29 April 2019

MATHS SOLVED IN STEPS: Profit and Loss - 05

31. By selling an item for Rs.15, a trader loses one sixteenth of what it costs him. The cost price of the item is
A. Rs.14        B. Rs.15          C. Rs.16            D. Rs.17
Answer : Option C
Explanation :
SP=15
Loss=CP÷16
Loss=CP-SP=CP-15
(CP÷16)=CP-15
(15 CP÷16)=15
(CP÷16)=1
CP=16


32. A fruit seller sells apples at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%?
A. 11.32                    B. 11                    C. 12                   D. 11.81
Answer : Option D
Explanation :
SP=9
Loss=20%
CP={100÷ (100-Loss%)}×SP={100÷ (10020)}×9={100÷80}×9=(5÷4)×9
To make a profit of 5%,
SP={(100+Gain%)÷100}×CP=[(100+5)
÷100]×CP
=(105÷100)×((5÷4)×9)=
=((21÷20)×(5÷4)×9)= 11.81

33. A trader gives 12% additional discount on the discounted price, after giving an initial discount of 20% on the labeled price of an item. The final sale price of the item is Rs.704. Find out the labeled price?
A. 1000                 B. 2000               C. 1200            D. 920
Answer : Option A
Explanation :
Let the labeled price=x
SP=704
Initial Discount=20%
Price after initial discount=x×(80÷100)
Additional discount=12%
Price after additional discount=x×(80÷100)×(88÷100)
But Price after additional discount=SP=704
x×(80÷100)×(88÷100)=704
x×(4÷5)×(22÷25)=704
x=704×(25÷22)×(5÷4)= 1000


34. John purchased a machine for Rs. 80,000. After spending Rs.5000 on repair and Rs.1000 on transport he sold it with 25% profit. What price did he sell the machine?
A. Rs.107000              B. Rs.107500               C. Rs.108500              D. None of these
Answer : Option B
Explanation :
CP=80,000+5000+1000=86000
Profit=25%
SP=[(100+Gain%)÷100]×CP
=[(100+25)÷100]×86000
=(125÷100)×86000
=(5÷4)×86000=5×21500=107500


35. A shopkeeper sells his goods at cost price but uses a weight of 800 gm instead of kilogram weight. What is his profit percentage?
A. 18%                    B. 40%              C. 25%                D. 20%
Answer : Option C
Explanation :
If a trader professes to sell his goods at cost price, but uses false weights, then
Gain%=[(Error÷ (True Value-Error))×100]%
So here profit percentage=[(200÷ (1000200))×100]%
=[(200÷800)×100]%=25%
* MATHS (SOLVED IN STEPS ==> Ratio and Proportion
* MATHS (SOLVED IN STEPS ==> Progressions
* MATHS (SOLVED IN STEPS ==> Percentage
* MATHS (SOLVED IN STEPS ==> Surds and Indices
* MATHS (SOLVED IN STEPS ==> Calendar
* MATHS (SOLVED IN STEPS ==> Square and cube
* MATHS (SOLVED IN STEPS ==> Simplification
* MATHS (SOLVED IN STEPS ==> Problems on Average
* MATHS (SOLVED IN STEPS ==> HCF & LCM 
* MATHS (SOLVED IN STEPS ==> Problems on Trains 
* MATHS (SOLVED IN STEPS ==> Problems on Age 
* MATHS (SOLVED IN STEPS ==> Pipe and Cisterns
* MATHS (SOLVED IN STEPS ==> ODD MAN
* MATHS (SOLVED IN STEPS ==> TIME & WORK



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